If from each of the three boxes containing 3 white and 1 black, 2 white and 2
black, 1 white and 3 black balls, one ball is drawn at random, then the probability
that 2 white and 1 black balls will be drawn is:
Statement I : If $A\subset B$ then B can be expressed as $B=A\cup(\overline{A}\cap B)$ and
P(A) > P(B).
Statement II : If A and B are independent events, then ($A$ and $\overline{B}$), ($\overline{A}$ and $B$)
and ($\overline{A}$ and $\overline{B}$) are also independent
In the light of the above statements, choose the most appropriate answer from the
options given below:
Consider n events ${{E}}_1,{{E}}_2\ldots{{E}}_n$ with respective probabilities ${{p}}_1,{{p}}_2\ldots{{p}}_n$. If $P\Bigg{(}{{E}}_1,{{E}}_2\ldots{{E}}_n\Bigg{)}=\prod ^n_{i=1}{{p}}_i$, then
Given three identical boxes B1 B2 and B3 each containing two balls. B1 containstwo golden balls. B2 contains two silver balls and B3 contains one silver and onegolden ball. Conditional probabilities that the golden ball is drawn from B1, B2, B3are ____,______,______ respectively